shad-go/speller/speller.go
erius 5bc4119abb Implemented speller
The solution is efficient, but unreadable
Since the performance is not the priority in this task, a prettier solution must be implemented
2024-06-04 03:24:20 +03:00

88 lines
1.8 KiB
Go

//go:build !solution
package speller
import (
"strings"
)
var numToDigits = []string{
"", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine",
}
var teens = []string{
"ten", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen",
}
var decs = []string{
"", "", "twenty", "thirty", "forty", "fifty",
"sixty", "seventy", "eighty", "ninety",
}
var large = []string{
"billion", "million", "thousand",
}
func digitsReversedSlice(n int64) []uint8 {
digits := make([]uint8, 12)
for i := 0; i < len(digits); i, n = i+1, n/10 {
digits[i] = uint8(n % 10)
}
return digits
}
func Spell(n int64) string {
if n == 0 {
return "zero"
}
sign := n < 0
if sign {
n = -n
}
num, digits := strings.Builder{}, digitsReversedSlice(n)
// 35 is the optimal number which gives approx needed
// space for the number in 1 allocation
num.Grow(len(digits) * 35)
if sign {
num.WriteString("minus ")
}
largeIndex, iters := 0, 0
for i := len(digits) - 1; i >= 0; i, largeIndex = i-3, largeIndex+1 {
first, second, third := digits[i-2], digits[i-1], digits[i]
if first == 0 && second == 0 && third == 0 {
continue
}
if iters != 0 {
num.WriteRune(' ')
}
hundreds := numToDigits[third]
if hundreds != "" {
num.WriteString(hundreds)
num.WriteString(" hundred")
if second != 0 || first != 0 {
num.WriteRune(' ')
}
}
if second > 1 {
num.WriteString(decs[second])
if first > 0 {
num.WriteRune('-')
num.WriteString(numToDigits[first])
}
} else if second == 1 {
num.WriteString(teens[first])
} else {
if first > 0 {
num.WriteString(numToDigits[first])
}
}
if largeIndex < len(large) {
num.WriteRune(' ')
num.WriteString(large[largeIndex])
}
iters++
}
return num.String()
}